MCQ
The angular momentum of electron in $'d'$ orbital is equal to
- A$2 \sqrt {3} \ \hbar$
- B$0 \ \hbar$
- ✓$\sqrt {6} \ \hbar$
- D$\sqrt {2} \ \hbar$
✓
Answer
Correct option: C.
$\sqrt {6} \ \hbar$
c
Angular momentum $=\sqrt{l(l+1)} \hbar$
Angular momentum $=\sqrt{l(l+1)} \hbar$
For $d$ orbital, $l=2$
Angular momentum $=\sqrt{2(2+1)} \hbar=\sqrt{6} \hbar$
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