MCQ
The angular speed of seconds needle in a mechanical watch is
  • $\frac{\pi }{{30}}\,rad/s$
  • B
    $2\pi \,rad/s$
  • C
    $\pi \,rad/s$
  • D
    $\frac{{60}}{\pi }\,rad/s$

Answer

Correct option: A.
$\frac{\pi }{{30}}\,rad/s$
a
(a)$\omega = \frac{{2\pi }}{T} = \frac{{2\pi }}{{60}} = \frac{\pi }{{30}}\,rad/s$

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