MCQ
The angular velocity of seconds hand of a watch will be
- A$\frac{\pi }{{60}}\ rad/\sec $
- ✓$\frac{\pi }{{30}}\ rad/sec$
- C$60\,\pi \,\,rad/sec$
- D$30\,\pi \,\,rad/sec$
$\omega = \frac{\theta }{t} = \frac{{2\pi }}{{60}} = \frac{\pi }{{30}}rad/sec$
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