MCQ
The approximate value of $(1.0002)^{3000}$ is
- ✓$1.6$
- B$1.4$
- C$1.8$
- D$1.2$
$= 1 + (3000)(0.0002) + \frac{{(3000)(2999)}}{{1.2}}{(0.0002)^2} +... $
We want to get answer correct to only one decimal places and as such we have left further expansion.
$= 1 + (3000)(0.0002)$ $= 1.6$
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