MCQ
The area bounded by curve ${y^2} = x,$ line $y = 4$ and $y -$ axis is
- A$\frac{{16}}{3}$
- ✓$\frac{{64}}{3}$
- C$7\sqrt 2 $
- DNone of these
$ = 16 \times 4 - \int_0^{16} {\sqrt x } dx = 64 - \left[ {\frac{{{x^{3/2}}}}{{3/2}}} \right]_0^{16} = \frac{{64}}{3}.$
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