MCQ
The atomic number of an element having the valency shell electronic configuration $4{s^2}4{p^6}$ is
- A$35$
- ✓$36$
- C$37$
- D$38$
✓
Answer
Correct option: B.
$36$
b
(b) Complete $E.C. = {[Ar]^{18}}3{d^{10}}4{s^2}4{p^6}.$
(b) Complete $E.C. = {[Ar]^{18}}3{d^{10}}4{s^2}4{p^6}.$
Hence no. of ${e^ - } = $ no. of protons $ = 36 = Z$.
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