MCQ
The atomic number of an element having the valency shell electronic configuration $4{s^2}4{p^6}$ is
  • A
    $35$
  • $36$
  • C
    $37$
  • D
    $38$

Answer

Correct option: B.
$36$
b
(b) Complete $E.C. = {[Ar]^{18}}3{d^{10}}4{s^2}4{p^6}.$

Hence no. of ${e^ - } = $ no. of protons $ = 36 = Z$.

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