MCQ
The atomic radii in periodic table among elements from right to left
- ADecreases
- ✓Increases
- CRemain constant
- DFirst decreases and then increases
✓
Answer
Correct option: B.
Increases
b
Atomic radius decreases from left to right within a period. This is caused by the increase in the number of protons and electrons across a period. One proton has a greater effect than one electron; thus electrons are pulled towards the nucleus, resulting in a smaller radius.
Atomic radius decreases from left to right within a period. This is caused by the increase in the number of protons and electrons across a period. One proton has a greater effect than one electron; thus electrons are pulled towards the nucleus, resulting in a smaller radius.
The atomic radii in periodic table among elements from right to left increases.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Which gives monosubstituted product
Which of the following electronic configuration is associated with the biggest jump between the second and third ionization energies?
How many mole of electrons are needed to convert one mole of nitrate ion to hydrazine ?
Which of the following are arranged in the decreasing order or dipole moment
For a reaction $aA(g) \rightleftharpoons bB(g)$ at equilibrium, the heat of reaction at constant volume is $1500\,cal$ more than that at constant pressure. If the temperature is $27\,^oC,$ then.
→The $IUPAC$ name of the compound $\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,OC{H_3}} \\
| \\
{C{H_3} - C{H_2} - CH - C{H_2} - OH}
\end{array}$ is
→{\,\,\,\,\,\,\,OC{H_3}} \\
| \\
{C{H_3} - C{H_2} - CH - C{H_2} - OH}
\end{array}$ is
Heat of neutralisation of one equivalent of an acid by one equivalent of a base is minimum when
Structure of $IF_4^ + $ and hybridization of iodine in this structure are
→${H_2} + {I_2}$ $\rightleftharpoons$ $2HI$ In the above equilibrium system if the concentration of the reactants at ${25\,^o}C$ is increased, the value of ${K_c}$ will
→Consider the above reaction, the compound $'A'$ is
→