MCQ
The average binding energy per nucleon is maximum for the nucleus:
- A$_2 \mathrm{H}^4 $
- B$_8 \mathrm{O}^{16} $
- ✓$_{26} \mathrm{Fe}^{56}$
- D$_{92} \mathrm{U}^{238}$
Binding energy per nucleon increases with atomic number. The greater the binding energy per nucleon the more stable is the nucleus.
For $_{26} \mathrm{Fe}^{56}$number of nucleons is $56.$
This is most stable nucleus, since maximum energy is needed to pull a nucleon away from it.
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