MCQ
The average binding energy per nucleon is maximum for the nucleus:
  • A
    $_2 \mathrm{H}^4 $
  • B
    $_8 \mathrm{O}^{16} $
  • $_{26} \mathrm{Fe}^{56}$
  • D
    $_{92} \mathrm{U}^{238}$

Answer

Correct option: C.
$_{26} \mathrm{Fe}^{56}$

Binding energy per nucleon increases with atomic number. The greater the binding energy per nucleon the more stable is the nucleus.
For $_{26} \mathrm{Fe}^{56}$number of nucleons is $56.$
This is most stable nucleus, since maximum energy is needed to pull a nucleon away from it.

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