MCQ
The average power consumed by the given circuit is......$W$
- A$9.6$
- ✓$4.8$
- C$26.66$
- D$13.33$
✓
Answer
Correct option: B.
$4.8$
b
$\mathrm{X}_{\mathrm{L}}=\omega \mathrm{L}=300 \times \frac{50}{3}=5000\, \Omega$
$\mathrm{X}_{\mathrm{L}}=\omega \mathrm{L}=300 \times \frac{50}{3}=5000\, \Omega$
$\mathrm{X}_{\mathrm{C}}=\frac{1}{\omega \mathrm{C}}=\frac{1}{300 \times \frac{10}{3} \times 10^{-6}}=1000\, \Omega$
$Z=\sqrt{R^{2}+\left(X_{L}-X_{C}\right)^{2}}=\sqrt{3000^{2}+(5000-1000)^{2}}$
$=\sqrt{3000^{2}+4000^{2}}=5000\,\Omega$
$\mathrm{P}=\mathrm{V} \times \mathrm{I} \cos \phi=\mathrm{V} \cdot \frac{\mathrm{V}}{\mathrm{Z}} \cdot \frac{\mathrm{R}}{\mathrm{Z}}=\left(\frac{\mathrm{V}}{\mathrm{Z}}\right)^{2} \mathrm{R}$
$=\left(\frac{200}{5000}\right)^{2} \times 300=4.8 \mathrm{\,W}$
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