MCQ
The best reagent for converting, 2-phenylpropanamide into 1-phenylethanamine is _____________.
- Aexcess H2/ Pt.
- BNaOH/ Br2.
- CNaBH4/ methanol.
- DLiAlH4/ ether.
✓
Answer
- NaOH/Br2.
Explanation:
$\text{CH}_3-\text{CH}-\text{CONH}_2\xrightarrow[\text{(Hofmann's bromamide reaction)}]{\text{Br}_2/\text{N}_\text{a}\text{OH}}\text{CH}_3-\text{CH}-\text{NH}_2\\\ \ \ \ \ \ \ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\ \ \ \ \ \ \ \ \ \ \ \ \text{C}_6\text{H}_5\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{C}_6\text{H}_5\\2-\text{Phenylpropanamide}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1-\text{Phenyletanamine}$
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