MCQ
The bond angle is minimum in
- ✓${H_2}Te$
- B${H_2}Se$
- C${H_2}O$
- D${H_2}S$
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$1.\,\,(CH_3)_2 - \mathop C\limits^ + - CH_2 - CH_3$
$2.\,\,(CH_3)_3 - \mathop C\limits^ + $
$3.\,\,(CH_3)_2 - |\mathop C\limits^ + H|$
$4.\,\,CH_3 - \mathop C\limits^ + H_2$
$5.\,\,\mathop C\limits^ + H_3$
$\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,O}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,||}\\
{CH \equiv C - C - OH}
\end{array}}\limits_{\rm{I}} $ $\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||}\\
{C{H_2} = CH - C - OH}
\end{array}}\limits_{{\rm{II}}} $ $\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||}\\
{C{H_3} - C{H_2} - C - OH}
\end{array}}\limits_{{\rm{III}}} $$\mathop {\begin{array}{*{20}{c}}
\,\,\,{C{H_3}\,\,\,\,\,\,O}\\
\,\,\,{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||}\\
{C{H_3} - CH - C - OH}
\end{array}}\limits_{{\rm{IV}}} $
$\mathop {Ph - OH}\limits_{(A)} ,\,\,\,\,\mathop {Ph - C{H_2} - OH}\limits_{(B)} ,\,\,\,\,\mathop {Ph - C{O_2}H}\limits_{(C)} ,\,\,\,\mathop {Ph - C{H_2}-\mathop N\limits^ \oplus {H_3}}\limits_{(D)} $