MCQ
The bond angle is minimum in
- ✓${H_2}Te$
- B${H_2}Se$
- C${H_2}O$
- D${H_2}S$
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$\begin{array}{*{20}{c}}
{Cl\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,} \\
{C{H_3} - CH - COOH}
\end{array}\mathop {\xrightarrow{{(i)\,N{H_3}}}}\limits_{1\,mole\,\,(ii)\,{H_2}O} [X]$
Product $[X]$ will be :
$CaCO _{3( s )}+2 HCl _{( aq )} \rightarrow CaCl _{2( aq )}+ CO _{2( g )}+2 H _{2} O _{( l )}$
[Calculate upto second place of decimal point]
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