MCQ
The bond angles of $NH_3 , NH^+_4$ and $NH^-_2$ are in the order
- A$NH_2^- > NH_3 > NH_4^+$
- ✓$NH_4^+ > NH_3 > NH_2^-$
- C$NH_3 > NH_2^- > NH_4^+$
- D$NH_3 > NH_4^+ > NH_2^-$
✓
Answer
Correct option: B.
$NH_4^+ > NH_3 > NH_2^-$
b
If an atom has lone pairs and bonded electron pairs, the greater lone pair-lone pair repulsions will cause bond angle to decrease between bonded atoms.
If an atom has lone pairs and bonded electron pairs, the greater lone pair-lone pair repulsions will cause bond angle to decrease between bonded atoms.
$NH _2^{-}$ has $2$ bond pairs and $2$ lone pairs of electrons.
$NH _3$ has $3$ bond pairs and $1$ lone pair.
$NH _4^{-}$ has $4$ bond pairs.
Bond pair - Bond pair electron repulsions $\,<\,$ Bond pair - Lone pair electron
repulsions $\,<\,$ Lone pair - Lone pair electron repulsions
Greater lone pair - lone pair repulsions among electrons causes the $H - N - H$
bond angle to decrease. This effect is greatest for $NH _2^{-}$, followed by $NH _3$.
Hence, the correct order is: $NH _4^{+}\,>\, NH _3\,>\, NH _2^{-}$
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