MCQ
The bond between carbon atom $(1)$ and carbon atom $(2)$ in compound $N \equiv C - CH = C{H_2}$ involves the hybridised carbon as
- A$s{p^2}$ and $s{p^2}$
- B$s{p^3}$ and $sp$
- ✓$sp$ and $s{p^2}$
- D$sp$ and $sp$
$N \equiv \mathop {\mathop C\limits_1 }\limits^{sp} - \mathop {CH}\limits_2^{s{p^2}} = \mathop {C{H_2}}\limits_3 $
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