MCQ
The bond order for $\text{O}^+_2,\text{C}_2$ are:
- A2.5, 2
- B2, 3
- C3, 2
- D1.5, 2.0
Explanation:
$\text{O}^+_2$ has bond order 2.5
$\text{B.O.}=\frac12(10-5)=\frac52$ In C2(12)
$\text{B.O.}=\frac12(8-4)=2$
$\text{B.O.}=\frac12(\text{N}_\text{b}-\text{N}_\text{a})$ where Nb is bonding and Na is antibonding electrons.
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