The bond order in N_2^ + ion is - Vidyadip

MCQ

The bond order in $N_2^ + $ ion is

A
$1$
B
$2$
✓
$2.5$
D
$3$

✓

Answer

Correct option: C.

$2.5$

(c) ${\rm{B}}{\rm{.O}}{\rm{.}} = \frac{{{\rm{No}}{\rm{. of }}{N_b} - {\rm{No}}{\rm{. of }}{N_a}}}{2}$$ = \frac{5}{2} = 2.5$.

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