MCQ
The bond order in $O_2^ + $ is
- A$2$
- ✓$2.5$
- C$1.5$
- D$3$
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$CH _{3} CH _{2} CH = CH _{2}$ $\xrightarrow[{Rh\,\,catalyst}]{{{H_2}/CO}}$
Statement $I$ : Aniline does not undergo Friedel-Crafts alkylation reaction.
Statement $II$ : Aniline cannot be prepared through Gabriel synthesis.
In the light of the above statements, choose the correct answer from the options given below:
then rate determining step will be

$C{H_3} - COOH\xrightarrow{{N{H_3}}}A\xrightarrow{\Delta }B\xrightarrow[{B{r_2}}]{{KOH}}C$
$(a)$ $Be _{2} C$
$(b)$ $CaC _{2}$
$(c)$ $Mg _{2} C _{3}$
$(d)$ $Al _{4} C _{3}$
