MCQ
The bond order of $NO$ molecule is
- A$1$
- B$2$
- ✓$2.5$
- D$3$
✓
Answer
Correct option: C.
$2.5$
(c) ${\rm{B}}{\rm{.O}}{\rm{.}} = \frac{{{\rm{No}}{\rm{. of bonding }}{e^ - } - {\rm{ No}}{\rm{. of antibonding }}{e^ - }}}{2}$ $ = \frac{{8 - 3}}{2} = \frac{5}{2} = 2.5$.
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