MCQ
The bonds present in $N_2O_5(s)$ is /are :
$(i)$ Ionic
$(ii)$ Covalent
$(iii)$ Coordinate
- A$(ii)$ , only
- B$(ii)$ and $(iii)$ only
- C$(i)$ and $(ii)$ only
- ✓$(i),\, (ii)$ and $(iii)$
$(i)$ Ionic
$(ii)$ Covalent
$(iii)$ Coordinate
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$\begin{array}{*{20}{c}}
O \\
{||} \\
{C{H_3} - C - N{H_2}}
\end{array}$ $\xrightarrow{{KOBr}}$ $(A)$
$\begin{array}{*{20}{c}}
O \\
{||} \\
{C{H_3} - C - N{H_2}}
\end{array}$ $\xrightarrow{{LiAlH_4}}$ $(B)$

Assertion $(A):$ $\mathrm{H}_2 \mathrm{Te}$ is more acidic than $\mathrm{H}_2 \mathrm{~S}$.
Reason $(R):$ The bond dissociation enthalpy of $\mathrm{H}_2 \mathrm{Te}$ is less than that of $\mathrm{H}_2 \mathrm{~S}$.
In the context of the above statements, choose the correct answer from the following options: