MCQ
The Bouveault-Blanc reduction involves
  • ${C_2}{H_5}OH/Na$
  • B
    $LiAl{H_4}$
  • C
    ${C_2}{H_5}Mg{X^ - }$
  • D
    $Zn/HCl$

Answer

Correct option: A.
${C_2}{H_5}OH/Na$
a
(a)$\underset{\text{Ethyl}\,\text{butyrate}}{\mathop{{{C}_{3}}{{H}_{7}}COO{{C}_{2}}{{H}_{5}}}}\,\xrightarrow{Na/{{C}_{2}}{{H}_{5}}OH}\underset{\text{Butyl}\,\text{alcohol}}{\mathop{{{C}_{3}}{{H}_{7}}C{{H}_{2}}OH}}\,$

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$\begin{array}{*{20}{c}}
  {C{H_3} - CH - C{H_3}\xrightarrow{{PB{r_3}}}X\xrightarrow{{{\text{Mg/ether}}}}Y\,\xrightarrow{{{{\text{H}}_2}{\text{O/}}{{\text{H}}^ + }}}} \\ 
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