Question
The Brewsters angle ${i }_{b}$ for an interface should be
✓
Answer
$\tan i_b =\frac{\mu_{2}}{\mu_{1}}=\frac{\mu_{2}}{1}$
$\mu_{2}>1$
$\therefore \tan i _{ b }>1$
$\therefore 90^{\circ}> i _{ b }>45^{\circ}$
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