MCQ
The $C - H$ bond distance is the longest in
- A${C_2}{H_2}$
- B${C_2}{H_4}$
- ✓${C_2}{H_4}B{r_2}$
- D${C_6}{H_6}$
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$\mathrm{CH}_{4}+\mathrm{I}_{2} \underset{\text { Reversible }}{\stackrel{\mathrm{hv}}{\longrightarrow}} \mathrm{CH}_{3}-\mathrm{I}+\mathrm{HI}$
$\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_2} - COOH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow[{ + CaO}]{{NaOH}}$