MCQ
The calculated spin only magnetic moment of $Cr ^{2+}$ lon is......$\, B.M.$
- A$2.84$
- B$3.87$
- ✓$4.90$
- D$5.92$
✓
Answer
Correct option: C.
$4.90$
c
$\mu=\sqrt{(n+2)}$ B.M. $=\sqrt{4(6)}==\sqrt{24}$ $B.M.$
$\mu=\sqrt{(n+2)}$ B.M. $=\sqrt{4(6)}==\sqrt{24}$ $B.M.$
$=4.90$ $B.M.$
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