MCQ
The capacitance of a capacitor is C. It is charged at a potential difference V. If now it is related to resistance, the amount of energy dilapidation will be:
- ✓$\frac{1}{2} CV ^2$
- B$CV ^2$
- C$\frac{C V^2}{3}$
- D$\frac{1}{2} QV ^2$
✓
Answer
Correct option: A.
$\frac{1}{2} CV ^2$
(a)$\frac{1}{2} CV ^2$
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