The capacitor $'C'$ is initially uncharged.  Switch $S_1$ is closed for a long time while $S_2$ remains open. Now at $t = 0$ , $S_2$ is closed while $S_ 1$ is opened. All the batteries are ideal and connecting wires are resistanceless. Find $INCORRECT$ statement
  • AAt time $t = 0$ (just after $S_2$ is closed), reading of ammeter is $\frac {E}{5R}$
  • BAt time $t = 0$ (just after $S_2$ is closed), reading of ammeter is zero
  • CHeat developed till time $t = 5\ RC\ ln\ 2$ in resistance $3R$ is $\frac {9}{40}CE^2$
  • DAfter time $t > 0$ charge on the capacitor follows the equation $CE\ e^{-t/5RC}$
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