Download App

STD 11 - rectangular cartensian co-ordinates — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - rectangular cartensian co-ordinates4 Marks
MCQ
The centroid of a triangle, whose vertices are $(2,1)$, $(5,2)$ and $(3,4)$, is
  • A
    $\left( {\frac{8}{3},\frac{7}{3}} \right)$
  • ✓
    $\left( {\frac{{10}}{3},\frac{7}{3}} \right)$
  • C
    $\left( { - \frac{{10}}{3},\frac{7}{3}} \right)$
  • D
    $\left( {\frac{{10}}{3}, - \frac{7}{3}} \right)$
✓

Answer

Correct option: B.
$\left( {\frac{{10}}{3},\frac{7}{3}} \right)$
b
(b)$x = \frac{{2 + 5 + 3}}{3} = \frac{{10}}{3}$ and $y = \frac{{1 + 2 + 4}}{3} = \frac{7}{3}$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

JEE STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

The sum of the series $6 + 66 + 666 + ..........$ upto $n$ terms is
→
The corner points of the bounded feasible region are $(60,0),(120,0),(60,40),(40,20)$ and $(20,30)$. For the objective function $z=5 x+10 y \ldots$

$(i)$ Maximum value of $z$.

$(ii)$ Minimum value of $z$.

$(iii)$ Maximum value of $z$ has at

$(iv)$ Minimum value of $z$ has at

→
In a class of $125$ students $70$ passed in Mathematics, $55$ in Statistics and $30$ in both. The probability that a student selected at random from the class has passed in only one subject is
→
$60$ words can be made using all the letters of the word $BHBJO,$ with or without meaning. If these words are written as in a dictionary, then the $50^{\text {th }}$ word is :
→
$\root 4 \of {(17 + 12\sqrt 2 )} = $
→
A student score the following marks in five tests : $45, 54, 41, 57, 43$. His score is not known for the sixth test. If the mean score is $48$ in the six tests, then the standard deviation of the marks in six tests is:
→
If $f(x)=\int \frac{1}{x^{1 / 4}\left(1+x^{1 / 4}\right)} dx , f(0)=-6$, then $f(1)$ is equal to :
→
What is the equation of the ellipse with foci $( \pm 2,\;0)$ and eccentricity $ = \frac{1}{2}$
→
If $a^3 + b^6 = 2$, then the maximum value of the term independent of $x$ in the expansion of  $(ax^{\frac{1}{3}}+bx^{\frac{-1}{6}})^9$ is, where $(a > 0, b > 0)$
→
The area of the region bounded by the parabola $(y-2)^{2}=(x-1)$, the tangent to it at the point whose ordinate is $3$ and the $\mathrm{x}$-axis is :
→