MCQ
The CFSE for octahedral $\left[ CoCl _6\right]^{+}$is corresponding to 18,000 (w.r.t wave number $cm ^{-1}$ ). The CFSE for tetrahedral $\left[ CoCl _4\right]^{2-}$ will be:
- A18000 cm -1
- B16000 cm -1
- ✓8000 cm -1
- D20000 cm -1
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$C{H_3}CHBrC{H_2}C{H_3}\xrightarrow{{alc.\,KOH}}$
$(i)$ $C{H_3}CH = CHC{H_3}$ (major product)
$(ii)$ $C{H_2} = CHC{H_2}C{H_3}$ (minor product)