The charge on any one of the $2\,\mu \,F$ capacitors and $1\,\mu \,F$ capacitor will be given respectively (in $\mu \,C$) as
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(d) Potential difference across both the lines is same i.e. $2\, V$. Hence charge flowing in line $2$
$Q = \left( {\frac{2}{2}} \right) \times 2 = 2\,\mu C$ So charge on each capacitor in line $(2)$ is $2\, µC$
$Q = \left( {\frac{2}{2}} \right) \times 2 = 2\,\mu C$ So charge on each capacitor in line $(2)$ is $2\, µC$
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