The circle x^2+ y^2- 3x - 4y + 2 = 0 cuts x-axis: - Vidyadip

MCQ

The circle $x^2+ y^2- 3x - 4y + 2 = 0$ cuts $x-$axis:

A
$(2, 0), (-3, 0)$
B
$(3, 0), (4, 0)$
C
$(1, 0), (-1, 0)$
✓
$(1, 0), (2, 0)$

✓

Answer

Correct option: D.

$(1, 0), (2, 0)$

$x^2+ y^2- 3x - 4y + 2 = 0$
$x-$axis will be cut when $y = 0$
put $y=0$
$x^2 - 3x + 2 = 0$
$(x - 2) (x - 1) = 0$
$x = 1, 2$
points $(1, 0), (2, 0)$

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