MCQ
The colour of a complex compound is due to:
  • A
    Promotion of $3d-$electrons of the central atom/ion to $4s-$orbital.
  • B
    Promotion of $3d-$electrons of the central atom/ion to $4p-$orbitals.
  • Promotion of $3d-$electrons of the central atom/ion to $d-$orbitals.
  • D
    Promotion of $4s-$electrons of the central atom/ion to $4p-$orbitals.

Answer

Correct option: C.
Promotion of $3d-$electrons of the central atom/ion to $d-$orbitals.
The colour of a complex compound is due to promotion of $3d-$electrons of the central atom/ion to $d-$orbitals..
The colour of the complex compound is due to $d−d$ electronic transition.The $d-$orbitals of a free transition metal atom or ion are degenerate $($all have the same energy$.)$
When transition metals form coordination complexes, the $d-$orbitals of the metal interact with the electron cloud of the ligands in such a manner that the $d-$orbitals become non$-$degenerate $($not all having the same energy$).$

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