MCQ
The colour of $KMnO_4$ is due to
  • Charge transfer from ligand to metal
  • B
    Charge transfer from metal to ligand
  • C
    $d-d$ transition
  • D
    $p-d$ transition

Answer

Correct option: A.
Charge transfer from ligand to metal
a
The $M n$ atom in $K M n O_{4}$ has +7 oxidation state with electron configuration $[A r] 3 d^{0} 4 s^{0}$.

since no unpaired electrons are present, $d-d$ transitions are not possible. The molecule should,

therefore, be colourless.

 

The colour of $K M n O_{4}$ is intense purple due to $L \rightarrow M$ (ligand to metal) charge transfer $2 p(L)$ of

O to $3 d ( M )$ of $Mn$.

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