MCQ
The colour of $KMnO_4$ is due to
- ✓Charge transfer from ligand to metal
- BCharge transfer from metal to ligand
- C$d-d$ transition
- D$p-d$ transition
since no unpaired electrons are present, $d-d$ transitions are not possible. The molecule should,
therefore, be colourless.
The colour of $K M n O_{4}$ is intense purple due to $L \rightarrow M$ (ligand to metal) charge transfer $2 p(L)$ of
O to $3 d ( M )$ of $Mn$.
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