MCQ
The combination of gates shown below yields


- A$NAND$ gate
- ✓$OR$ gate
- C$NOT$ gate
- D$XOR $ gate

$X=(\overline{\bar{A}+\bar{B}})=\bar{\bar{\underset{\scriptscriptstyle\centerdot}{A}}}\cdot \bar{\bar{B}}=A+B\,\Rightarrow $ $OR$ gate
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.



