MCQ
The common factor of $24a^3b^4, 36a^4c^4$ and $48a^3b^2c$ is:
- A$24a^3$
- B$36a^3$
- ✓$12a^3$
- D$48a^3$
✓
Answer
Correct option: C.
$12a^3$
C. $12a^3$
Solution:
$24a^3b^4 = 2 \times 2 \times 2 \times 3 \times a \times a \times a \times b \times b \times b \times b$
$36a^4c^4 = 2 \times 2 \times 3 \times 3 \times a \times a \times a \times a \times c \times c \times c \times c$
$48a^3b^2c = 2 \times 2 \times 2 \times 2 \times 3 \times a \times a \times a \times b \times b \times c$
Solution:
$24a^3b^4 = 2 \times 2 \times 2 \times 3 \times a \times a \times a \times b \times b \times b \times b$
$36a^4c^4 = 2 \times 2 \times 3 \times 3 \times a \times a \times a \times a \times c \times c \times c \times c$
$48a^3b^2c = 2 \times 2 \times 2 \times 2 \times 3 \times a \times a \times a \times b \times b \times c$
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