MCQ
The complement of $(90^\circ- a)$ is:
- A$-a$
- B$90^\circ + a$
- C$90^\circ - a$
- ✓$a$
Let the complement be $y$ Two angles are complementary if their sum is $90^\circ$
$\therefore 90^\circ - a + y = 90^\circ$
$⇒ y = a$
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