MCQ
The complete solution of the inequation ${x^2} - 4x < 12\,{\rm{ is}}$
  • A
    $x < - \,2$ or $x > 6$
  • B
    $ - \,6 < x < 2$
  • C
    $2 < x < 6$
  • $ - \,2 < x < 6$

Answer

Correct option: D.
$ - \,2 < x < 6$
d
(d) ${x^2} - 4x < 12$

==> ${x^2} - 4x - 12 < 0$ ==> ${x^2} - 6x + 2x - 12 < 0$

==> $(x - 6)(x + 2) < 0$ ==> $ - 2 < x < 6$.

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