MCQ
The complex $[Co(NH_3)_5Br]SO_4$ will give white $ppt.$ with :
- ✓D and B correct.
- B$AgNO_3$
- C$KI$
- D$BaCl_2$
✓
Answer
Correct option: A.
D and B correct.
a
The complexes $\left[ Co \left( N H _{3}\right)_{5} Br \right] SO _{4}$ and $\left[ Co \left( NH _{3}\right)_{5} SO _{4}\right] Br$ can be
distinguished by $B a C l_{2}$ and $A g N O_{3}$
$\left[ Co \left( NH _{3}\right)_{5} Br \right] SO _{4}$ furnishes sulphate ions in the solution which react with
$B a C l_{2}$ to form white ppt of $B a S O_{4}$
$\left[ Co \left( NH _{3}\right)_{5} SO _{4}\right] Br$ furnishes bromide ions in the solution which reacts with
$A g N O_{3}$ to form yellow ppt of $A g B r$
$\left[ Co \left( NH _{3}\right)_{5} Br \right] SO _{4}+ BaCl _{2} \rightarrow\left[ Co \left( NH _{3}\right)_{5} Br \right] Cl _{2}+\underset{\text { White }}{ BaSO _{4}} \downarrow$
$\left[C o\left(N H_{3}\right)_{5} S O_{4}\right] B r+A g N O_{3} \rightarrow\left[C o\left(N H_{3}\right)_{5} S O_{4}\right] N O_{3}+A g B r \downarrow$
Optins D and B correct.
The complexes $\left[ Co \left( N H _{3}\right)_{5} Br \right] SO _{4}$ and $\left[ Co \left( NH _{3}\right)_{5} SO _{4}\right] Br$ can be
distinguished by $B a C l_{2}$ and $A g N O_{3}$
$\left[ Co \left( NH _{3}\right)_{5} Br \right] SO _{4}$ furnishes sulphate ions in the solution which react with
$B a C l_{2}$ to form white ppt of $B a S O_{4}$
$\left[ Co \left( NH _{3}\right)_{5} SO _{4}\right] Br$ furnishes bromide ions in the solution which reacts with
$A g N O_{3}$ to form yellow ppt of $A g B r$
$\left[ Co \left( NH _{3}\right)_{5} Br \right] SO _{4}+ BaCl _{2} \rightarrow\left[ Co \left( NH _{3}\right)_{5} Br \right] Cl _{2}+\underset{\text { White }}{ BaSO _{4}} \downarrow$
$\left[C o\left(N H_{3}\right)_{5} S O_{4}\right] B r+A g N O_{3} \rightarrow\left[C o\left(N H_{3}\right)_{5} S O_{4}\right] N O_{3}+A g B r \downarrow$
Optins D and B correct.
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