MCQ
The compound in which carbon uses only its $s{p^3}$ hybrid orbitals for bond formation is
- A$HCOOH$
- B${(N{H_2})_2}CO$
- ✓${(C{H_3})_3}COH$
- D${(C{H_3})_3}CHO$
All the carbon atoms are $s{p^3}$ hybridized.
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| Molecule | $P-X$ (axial) bond length | $P-X$ (Equitorial) bond length |
| $PF_5$ | $a$ | $b$ |
| $PF_4CH_3$ | $c$ | $d$ |
| $PF_3 (CH_3)_2$ | $e$ | $f$ |
| $PCl_5$ | $g$ | $h$ |
According to given information choose the incorrect order of bond length