MCQ
The compound $(SiH_3)_3N$ is expected to be
  • A
    pyramidal and more basic than $(CH_3)_3N$
  • planar and less basic than $(CH_3)_3N$
  • C
    pyramidal and less basic than $(CH_3)_3N$
  • D
    planar and more basic than $(CH_3)_3N$

Answer

Correct option: B.
planar and less basic than $(CH_3)_3N$
b
The compound $\left( SiH _3\right)_3 N$ is planar and less basic than $\left( CH _3\right)_3 N$ because the lone pair of electrons on $N$ in $\left( SiH _3\right)_3 N$ are used in $p \pi- d \pi$ back bonding by $Si$ atom while such $p \pi- d \pi$ bonding is not possible in $\left( CH _3\right)_3 N$ due to absence of vacant $d$-orbital in carbon.

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