MCQ
The compound that can work both as oxidising and reducing agent is
- A$KMn{O_4}$
- ✓${H_2}{O_2}$
- C$Ba{O_2}$
- D${K_2}C{r_2}{O_7}$
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$(i)$ $C{H_3} - \mathop C\limits^ + H - C{H_3}$
$(ii)$ $C{H_3} - \mathop C\limits^ + H - O - C{H_3}$
$(iii)$ $C{H_3} - \mathop C\limits^ + H - CO - C{H_3}$
(Given : $R =8.3 \,J \,K ^{-1}\, mol ^{-1}$ )
$\begin{array}{*{20}{c}}
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - CH = C{H_2}\,\,\,\,\,} \\
{\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,\,\,C{H_{3\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}}}
\end{array}\xrightarrow[{(ii)\,NaB{H_4}}]{{(i)\,Hg{{(OAc)}_2};{H_2}O}}$