- A$CH _3 Cl$
- B$CH _2 Cl _2$
- C$CHCl _3$
- ✓$CCl _4$
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$\frac{d[NH_3]}{dt} = 2 \times 10^{-4} \, mol \,L^{-1} \, s^{-1}$ , the value of $\frac{-d[H_2]}{dt}$ would be .................. $mol \,L^{-1} \, s^{-1}$
$Z$ is :
$A$. All group $16$ elements form oxides of general formula $\mathrm{EO}_2$ and $\mathrm{EO}_3$ where $\mathrm{E}=\mathrm{S}, \mathrm{Se}, \mathrm{Te}$ and Po. Both the types of oxides are acidic in nature.
$B$. $\mathrm{TeO}_2$ is an oxidising agent while $\mathrm{SO}_2$ is reducing in nature.
$C$. The reducing property decreases from $\mathrm{H}_2 \mathrm{~S}$ to $\mathrm{H}_2 \mathrm{Te}$ down the group.
$D$. The ozone molecule contains five lone pairs of electrons.
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