MCQ
The compound which will give negative iodoform test is
- A$C{H_3}CHO$
- B$C{H_3}C{H_2}OH$
- CIsopropyl alcohol
- ✓Benzyl alcohol
${C_6}{H_5} - C{H_2} - OH\xrightarrow{{NaOH/{I_2}}}{\text{No}}\,\,{\text{yellow}}\,\,ppt.$
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$I$. $\log \,\,K\, = \,\frac{{nF{E^o}}}{{2.303\,RT}}$
$II$. $K\, = \,{e^{\frac{{nF{E^o}}}{{RT}}}}$
$III$. $\log \,\,K\, = -\,\frac{{nF{E^o}}}{{2.303\,RT}}$
$IV$. $\log \,\,K\, = 0.4342\,\,\frac{{-nF{E^o}}}{{RT}}$
Choose the correct statement $(s)$.
| List$-I$ | List$-II$ |
| $(a)$ $\left[ Co \left( NH _{3}\right)_{6}\right]\left[ Cr ( CN )_{6}\right]$ |
$(i)$ Linkage isomerism |
| $(b)$ $\left[ Co \left( NH _{3}\right)_{3}\left( NO _{2}\right)_{3}\right]$ |
$(ii)$Solvate isomerism |
| $(c)$ $\left[ Cr \left( H _{2} O \right)_{6}\right] Cl _{3}$ |
$(iii)$ Co-ordination isomerism |
| $(c)$ $cis-[CrCl$ $\left._{2}(\text { ox })_{2}\right]^{3-}$ | $(iv)$ Optical isomerism |
Choose the correct answer from the options given below: