MCQ
The compound $YB{a_2}C{u_3}{O_7}$ which shows superconductivity has copper in oxidation state ........ Assume that the rare earth element Yttrium is in its usual $ + \,3$ oxidation state
- A$3/7$
- ✓$7/3$
- C$3$
- D$7$
$3 + 2 \times 2 + 3x - (2 \times 7) = 0$
$3 + 4 + 3x - 14 = $$3x = 7$
$x = \frac{7}{3}$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\begin{array}{*{20}{c}}
{\,\,C{H_3}\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - CH = C{H_2}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,C{H_3}\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow[{2.\,KOH - EtOH,\,heat}]{{1.\,HBr}}$
The major end product formed is :-
