MCQ
The conjugate acid of ${H_2}PO_4^ - $ is
- ✓${H_3}P{O_4}$
- B${H_2}PO_4^ - $
- C$PO_4^{3 - }$
- D${H_3}{O^ + }$
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$Cu ( s )+2 Ag ^{+}( aq ) \rightleftharpoons Cu ^{2+}( aq )+2 Ag ( s )$
The equilibrium constant for the reaction.$\frac{1}{2} Cu ^{2+}( aq )+ Ag ( s ) \rightleftharpoons \frac{1}{2} Cu ( s )+ Ag ^{+}( aq )$ is $x \times 10^{-8}$. The value of $x$ is (Nearest Integer)