MCQ
The conjugate acid of $NH_2^-$ is
- A$NH_4^+$
- ✓$NH_3$
- C$NH_2OH$
- D$N_2H_4$
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$A$, (molecular formula $\left.\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{2}\right)$ with a straight chain structure gives a $C_{4}$ carboxylic acid. $A$ is :
$A \frac{{Li} {A} {H} {H}_{4}}{{H}_{3} {O}^{+}} \longrightarrow B \stackrel{\text { Oxidation }}{\longrightarrow} {C}_{4}-$ carboxylic acid

$(ii)$ $CH _{3} COOH$
$(iii) $ $C _{6} H _{5} COOH$
$(iv)$ $CH _{3} CH _{2} COOH$
Correct order of $pK _{ a }$ value is :