MCQ
The conversion, $PhCN \to PhCOCH_3,$ can be achieved most conveniently by reaction with
- ✓$CH_3MgBr$ followed by hydrolysis
- B$I_2 - NaOH, CH_3I.$
- Cdil. $H_2SO_4$ followed by reaction with $CH_2N_2$
- D$LAH$ followed by reaction with $CH_3I$
✓
Answer
Correct option: A.
$CH_3MgBr$ followed by hydrolysis
a
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→$\underset{1}{\mathop{\begin{matrix}
O\,\,\,\,\,\,\,\,\,\,\,\, \\
||\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}COCHC{{H}_{3}} \\
\end{matrix}}}\,$ $\underset{2}{\mathop{\begin{matrix}
\,\,\,\,O \\
\,\,\,\,|| \\
C{{H}_{3}}CCl \\
\end{matrix}}}\,$ $\underset{3}{\mathop{\begin{matrix}
O\,\,\,\,\,\,\,\,\, \\
||\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}CNHC{{H}_{3}} \\
\end{matrix}}}\,$
The compound $I$ and $II$ are related as
→$\mathop {\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{COOH\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{H - C - OH\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}} \\
{Br - C - H\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,\,COOC{H_3}}
\end{array}}\limits_{(I)} $ $\mathop {\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,COOC{H_3}\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{H - C - Br\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}} \\
{HO - C - H\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,\,\,\,\,\,COOH\,\,\,\,\,\,\,\,}
\end{array}}\limits_{(II)} $
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