MCQ
The correct acidity order of the following is


- ✓$(III) > (IV) > (II) > (I)$
- B$(IV) > (III) > (I) > (II)$
- C$(III) > (II) > (I) > (IV)$
- D$(II) > (III) > (IV) > (I)$

Carboxylic acid is more acidic than phenol. When an electron releasing group is present in the para position to $-COOH$ group in aromatic carboxylic acid, the acidity is reduced.
When $Cl$ atom is present in the para position to $-OH$ group in phenol, it increases its acidity.
Here $Cl$ atom withdraws electron density from the ring and stabilizes the phenoxide ion.
Option $A$ is correct.
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