MCQ
The correct Boolean operation represented by the circuit diagram drawn is
- A$AND$
- B$OR$
- ✓$NAND$
- D$NOR$
✓
Answer
Correct option: C.
$NAND$
c
$\begin{array}{|c|c|c|}\hline A & {B} & {Y} \\ \hline 0 & {0} & {1} \\ \hline 0 & {1} & {1} \\ \hline 1 & {0} & {1} \\ \hline 1 & {1} & {0} \\ \hline\end{array}$
$\begin{array}{|c|c|c|}\hline A & {B} & {Y} \\ \hline 0 & {0} & {1} \\ \hline 0 & {1} & {1} \\ \hline 1 & {0} & {1} \\ \hline 1 & {1} & {0} \\ \hline\end{array}$
It is a $NAND$ Gate
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