MCQ
The correct evaluation of $\int_0^{\pi /2} {\sin x\,\sin 2x} $ is
  • A
    $\frac{4}{3}$
  • B
    $\frac{1}{3}$
  • C
    $\frac{3}{4}$
  • $\frac{2}{3}$

Answer

Correct option: D.
$\frac{2}{3}$
d
(d) Let $I = \int_0^{\pi /2} {\sin x\sin 2x\,dx} $

$= 2\int_0^{\pi /2} {{{\sin }^2}x\cos xdx} $

Put $t = \sin x \Rightarrow dt = \cos x\,dx$

Now, $I = 2\int_0^1 {{t^2}dt = \frac{2}{3}[{t^3}]_0^1 = \frac{2}{3}} $.

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